nthroot.RdCompute the real n-th root of real numbers.
nthroot(x, n)Computes the n-th root real numbers of a numeric vector x,
while x^(1/n) will return NaN for negative numbers,
even in case n is odd. If some numbers in x are negative,
n must be odd. (This is different in Octave)
Returns a numeric vector of solutions to \(x^{1/n}\).
nthroot(c(1, -2, 3), 3) #=> 1.000000 -1.259921 1.442250
#> [1] 1.000000 -1.259921 1.442250
(-2)^(1/3) #=> NaN
#> [1] NaN