sort and order methods for data.frame and matrix, sorting it in lexicographic order.R/misc.utilities.R
sort.data.frame.RdThese function return a data frame sorted in lexcographic order or a permutation that will rearrange it into lexicographic order: first by the first column, ties broken by the second, remaining ties by the third, etc..
order(..., na.last = TRUE, decreasing = FALSE)
# Default S3 method
order(..., na.last = TRUE, decreasing = FALSE)
# S3 method for class 'data.frame'
order(..., na.last = TRUE, decreasing = FALSE)
# S3 method for class 'matrix'
order(..., na.last = TRUE, decreasing = FALSE)
# S3 method for class 'data.frame'
sort(x, decreasing = FALSE, ...)Ignored for sort. For order, first argument is
the data frame to be ordered. (This is needed for compatibility with
order.)
See order documentation.
Whether to sort in decreasing order.
A data.frame to sort.
For sort, a data frame, sorted lexicographically. For
order, a permutation I (of a vector 1:nrow(x)) such
that x[I,,drop=FALSE] equals x ordered lexicographically.
data.frame, sort, order,
matrix
data(iris)
head(iris)
#> Sepal.Length Sepal.Width Petal.Length Petal.Width Species
#> 1 5.1 3.5 1.4 0.2 setosa
#> 2 4.9 3.0 1.4 0.2 setosa
#> 3 4.7 3.2 1.3 0.2 setosa
#> 4 4.6 3.1 1.5 0.2 setosa
#> 5 5.0 3.6 1.4 0.2 setosa
#> 6 5.4 3.9 1.7 0.4 setosa
head(order(iris))
#> [1] 14 9 39 43 42 4
head(sort(iris))
#> Sepal.Length Sepal.Width Petal.Length Petal.Width Species
#> 14 4.3 3.0 1.1 0.1 setosa
#> 9 4.4 2.9 1.4 0.2 setosa
#> 39 4.4 3.0 1.3 0.2 setosa
#> 43 4.4 3.2 1.3 0.2 setosa
#> 42 4.5 2.3 1.3 0.3 setosa
#> 4 4.6 3.1 1.5 0.2 setosa
stopifnot(identical(sort(iris),iris[order(iris),]))