Remove matches, i.e. replace them with "".
str_remove(string, pattern)
str_remove_all(string, pattern)Input vector. Either a character vector, or something coercible to one.
Pattern to look for.
The default interpretation is a regular expression, as described in
vignette("regular-expressions"). Use regex() for finer control of the
matching behaviour.
Match a fixed string (i.e. by comparing only bytes), using
fixed(). This is fast, but approximate. Generally,
for matching human text, you'll want coll() which
respects character matching rules for the specified locale.
Match character, word, line and sentence boundaries with
boundary(). An empty pattern, "", is equivalent to
boundary("character").
A character vector the same length as string/pattern.
str_replace() for the underlying implementation.
fruits <- c("one apple", "two pears", "three bananas")
str_remove(fruits, "[aeiou]")
#> [1] "ne apple" "tw pears" "thre bananas"
str_remove_all(fruits, "[aeiou]")
#> [1] "n ppl" "tw prs" "thr bnns"